Question

vampire enters a town and bites 2 person every night. The bitten 2 persons grows in to two big vampires and bites 4 persons the next night. These 4 vampires bites 6 people the next night and the 6 bites 8 and so on.......how many vampires will be there on the 5th night?
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Answer 1

Answer:

39

Explanation:

1st night = total vampires 1+2 = 3 . (1)-already  , (2)- bitten

2nd night = total vampires 3+2+4 = 9 . (3)-already  , (2)- bitten by first vampire ,  (4)bitten by growing vampires

3rd night = total vampires 9+2+6 = 17 . (9)-already  , (2)- bitten by first vampire,  (6)bitten by growing vampires

4th night = total vampires 17+2+8= 27 . (17)-already  , (2)- bitten by first vampire,  (8)bitten by growing vampires

5th night = total vampires 27+2+10=39 . (27)-already  , (2)- bitten by first vampire,  (10)bitten by growing vampires

total vampires on 5th night = 39

Answer 2

Answer:

there would be 34 vampire´s in town

Explanation:

Because if there was 1 vampire the first night and then bites 2 people there would be 3 vampires the the two new vampire´s would bite 2 people each so that makes 7 vampires then so on and so on until the 5th day

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