Question

van hoff s factor equation ​

Answer 1

Answer:

I = 1+ (n-1)a

n= no of particles associated/ dissociated

a = dissociation/ association constant

Answer 2

$\huge\red{\boxed{\bold{Answer}}}$

$\large\underline\mathrm\pink{We}$ have so far discussed ideal solutions containing the solute which neither undergoes dissociation nor association. The solute undergoes dissociation or association, the number of solute particules change as a result of which abnormal results are obtained for colligative properties and molecular weight of solutes as the colligative properties depend upon the number of solute particles.

In order to account for such abnormal results, van't Hoff introduced a factor '$\large\underline\mathrm\orange{i}$' known as van't Hoff factor, expressed as

$\large\underline\mathrm\orange{i}$ = observed magnetude of any colligative property/normal magnitude of the same colligative property.

$\implies$ normal molecules weight/observed mil. weight

$\large\underline\mathrm\red{'i' \: can \: also \: be \: calculated \:as}$

$\large\underline\mathrm\orange{i}$ = moles of solute particules after dissociation/association / moles of solute particles originall takes

$\implies$ observer molality/calculate molality.

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