Question

Van't hoff factor for a dilute aqueous solution of hcn is 1.00002 .the percent degree of dissociation of the acid is​

Answer 1

Answer:

degree of dissociation (a) = I -1/n-1

a = 1.00002 - 1/2-1

a = 0.0002

Answer 2

Concept Introduction:-

It is a type of branch in which maths are deals with their own properties and also manipulation of numbers.

Given:-

We have been given an amount.

To Find:-

We have to find present degree.

Solution:-

According to the problem

degree of dissociation (a) = I -1/n-1

a = 1.00002 - 1/2-1

a = 0.0002

Final Answer:-

The final answer is  0.0002

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