Question

Van't Hoff factor(i) for 30% dissociation of K4[Fe(CN)6] is -
(1) 1.1
(2) 1.2
(3) 2.5
(4) 2.2​

Answer 1

Answer:

(4)

Explanation:

K4[Fe(CN)6]3 -> 4Fe 3+ + [Fe(CN)6]3-

degree of dissociation = 0.3

i = 1+4×0.3 = 2.2

Answer 2

(4) 2.2

hope this will help u