Question

Van't hoff factor of ca(no3)is

Answer 1

The Van't Hoff factor of Ca(NO3)2 when it is completely dissociated is 1/3......

Answer 2

Van't hoff factor of $Ca(NO_3)_2$ is 3

Explanation:

Van't Hoff's factor is the ratio of observed colligative property to the calculated Colligative property.

$i=\frac{\text {observed colligative property}}{\text {Calculated Colligative property}}$

$Ca(NO_3)_2\rightarrow Ca^{2+}+2NO_3^-$

When   dissociates completely, it gives 3 ions , thus vant hoff factor is 3.

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