Question

Van't hoff factor of hg2cl2 in its aqueous solution will be

Answer 1

in this any equal to 3...
Alpha is equal to 0.8.... So I =2.6

Answer 2

Hey there,

● Van't Hoff factor -
- Van't Hoff factor is the number of particles formed in a solution from one formula unit of solute.


● Answer -
i = 3

● Explanation -
Here, you didn't mention degree of ionization.
SO we'll consider α = 100%.

Dissociation of Hg2Cl2 occurs as follows -
Hg2Cl2 ---> (Hg2)2+ + 2Cl-

Total ions formed
n = 1 + 2 = 3

For 100% ionization, i = n = 3.

Therefore, van'f Hoff factor is 3 for Hg2Cl2.

Hope this helps yoy...