Question

Van't Hoff factor of Hg2Cl2 in its aqueous solution will be (Hg2cl2) in its aqueour solution will be (Hg2cl2 is 80% ionized in the solution​

Answer 1

Answer:

hey mate.....

here is your answer

here alpha is given to be 80 % or 0.8

as we know.. ..

Hg2Cl2 gives (Hg2 )2+....and 2Cl-

so n= 1+2=3

alpha = vant Hoff factor (i) - 1/ n-1

so putting all the values we get

0.8=i-1/3-1

so i= 2.6

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Answer 2

was it help full dear mate

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