Chemistry, asked by richaguptat, 7 months ago

Van’t Hoff factors of aqueous solutions of X,Y,Z are 1.8, 0.8 and 2.5, Hence, their
a) boiling point: Z < X < Y
b) freezing point: Z < X < Y
c) osmotic pressure: X = Y = Z
d) vapour pressure Y < x < Z

Answers

Answered by sudhavelmurugan56
3

Answer:

i think answer is d

Explanation:

relative lowering in vp &other 3 colligative prop. is proportional to i(vant hoff's factor ) ,ac. to this i is greater for z,x,y...!

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