Question

वन ऑफ द एक्सटीरियर एंगल ऑफ द ट्रायंगल इज 100 डिग्री and the interior angle are in the ratio 2.3 find all the angle in the triangle ​

Answer 1

Using the theorem that if the side of a triangle is produced then the interior angle is equal to the sum of two interior opposite angles of the triangle.

Let ΔABC be a triangle where the side BC is produced.

By the theorem we have

∠A+∠B=100°…………..(1)

It is given that the interior opposite angles are equal i.e., ∠A=∠B.

∴ Equation (1) becomes

2∠A=100°

⇒∠A=50°

⇒∠B=50°

Using angle sum property of a triangle,

Sum of all angles of a triangle =180°

⇒∠A+∠B+∠C=180°

⇒100+∠C=180°

[from (1)]

⇒∠C=180°−100°

⇒∠C=80°

Hence ∠A=50°

∠B=50°

∠C=80°

$\large\bold{\textbf{\textsf{{\color{silver}{Hope it helps uh !!}}}}}$

Answer 2

Step-by-step explanation:

Using the theorem that if the side of a triangle is produced then the interior angle is equal to the sum of two interior opposite angles of the triangle.

Let ΔABC be a triangle where the side BC is produced.

By the theorem we have

∠A+∠B=100°…………..(1)

It is given that the interior opposite angles are equal i.e., ∠A=∠B.

∴ Equation (1) becomes

2∠A=100°

⇒∠A=50°

⇒∠B=50°

Using angle sum property of a triangle,

Sum of all angles of a triangle =180°

⇒∠A+∠B+∠C=180°

⇒100+∠C=180°

[from (1)]

⇒∠C=180°−100°

⇒∠C=80°

Hence ∠A=50°

∠B=50°

∠C=80°

\large\bold{\textbf{\textsf{{\color{silver}{Hope it helps uh !!}}}}}Hope it helps uh !!