Question

vant hoff factor of 0.1M cacl2 solution is

Answer 1

Answer:

3

Explanation:

Vant Hoff's factor (i) = 1 + (n-1) alpha

where alpha is the degree id dissociation which is 1 for complete dissociation.

i = 1+ (n-1) , n is the no . of particles produced on dissociation of Cacl2 == Ca+2 + 2Cl-.

therefore 3 particles are produced. so n=3.

i = 1+ (3-1) = 3

in short ,Vant hoff factor for complete dissociation of Ionic compounds is the no. of ions it produces on complete dissociation.