Question

Vapour density of a gas is 8 at stp mass of 11.2 which gas is this

Answer 1

at stp., 1 mole of gas ----------->22.4 L

"x" mole of gas-----------> 11.2L

x=(11.2/22.4)=0.5 moles.

vapour density =(molecular mass/2)

molecular mass=2* vapour density

molecular mass =2*8=16 Amu.

1 mole ----------------------->16 amu

0.5 mole----------------------->"y" amu

y=(0.5*16)=8 amu.

so, at 11.2L ,STP,,, mass will be=8amu.

:)