Vapour density of a metal chloride is 66. It oxide contain 53% of metal. Atomic wt of the metal is appropriate
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2×v.d=molar mass
2×66=132 is the molar mass of the metal
It's oxide has 53%metal ......ie....100 gm oxide will have 53gm metal
47 gm of oxygen ...ie.... .approximately 3 moles of oxygen.
So one mole of metal has 3 atoms of oxygen .this implies that it is to form Al2O3.
Now let's cross check
Atomic mass of Al is 26.5
26.5×2=53
It's chloride is AlCl3
26.5+3×35.5=26.5+106.5=133
Atomic wthe of the metal is 26.5
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