Question

vapour density of a metal chloride is 77. The equivalent mass is 3.Its atomic mass would be

Answer 1

Molecular weight can be calculated as follows:

Molecular weight = Vapour density X 2

Molecular weight = 77 X 2 = 154 g

Molecular weight of metal chloride = 154 g

Molecular weight of chlorine (Cl) = 35.5 g

Since the molecular weight of Cl is 35.5 g, metal chloride could have 4 Cls in its molecular formula.

So the possible molecular formula is MCl4

Molecular weight of metal chloride = Molecular weight of metal + (Molecular weight of Cl X 4)

Molecular weight of metal chloride = 12 + (35.5 X 4) = 154

So Equivalent weight of metal = 12/4 = 3

Atomic mass of metal = 12