Vapour density of ammonia is 8.5, then 85 g of
NH, at NTP will occupy.
(1) 22.4L
(2) 112 L
(3) 224 L
(4) 1120 L
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Answer:
vapour density of ammonia is 8.5
so molecular mass of ammonia =2*vapour density
mol. mass=2*8.5=17
number of moles of ammonia=85/17=5
according to NTP one mole =22.4l
5 mole=22.4*5l
85 g of NH3 will occupy = 112l
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