Question

Vapour density of an ideal gas is 11.2.what is the volume occupied by 2 gram of this gas at STP?

Answer 1

Answer:

Explanation:

V.D. = MM /2

11.2 = MM/2

MM = 22.4 g

n = 2.4 / 22.4

n= 24/ 224

24/224 = v / 22.4

v = 24 x 22.4 / 224

v = 2.4 l

Answer 2

Answer:

2L

Explanation:

2 × Vapor density = molecular mass

2 × 11.2 = M.M

22.4 u = M.M

n (no of moles) = 2/22.4 = 1/ 11.2 moles

1 mole = 22.4 L

1/11.2 L = 22.4 × 1/11.2 = 2L