Chemistry, asked by keertanachiguru1560, 1 year ago

Vapour density of an oxide of nitrogen is 38. Its molecular formula is

Answers

Answered by Anonymous
11

Explanation:

It may be defined as mass of a certain volume of a substance divided by mass of same volume of hydrogen. vapour density = mass of n molecules of gas / mass of n molecules of hydrogen. (and thus: molar mass = ~2 × vapour density) For example, vapour density of mixture of NO2 and N2O4 is 38.

Answered by bhumithotadbhumithot
1

Explanation:

molecular formula= 2×vapour density

=2 × 38

=76

hence in the given option only N2O3 has 76 g molecular mass..it is correct option

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