Question

Vapour density of metal chloride is 77 equivalent weight of metal is 3, then its atomic weight will

Answer 1

Answer:

Explanation:

Solution :

Vapour density =77

Mol. wt =2×77=154=2×77=154

Let the valency of element is x

Then , Atomic weight = Eq.wt \times valency

=3×x=3×x

the formula MClxMClx

Mol. wt =3x+35.5x=38.5x=3x+35.5x=38.5x

Equating this with the mol.wt.as calculated from V.D

38.5x=15438.5x=154

x=15438.5x=15438.5=4=4

Hence , correct atomic wt. of element

=Eq.wt×valency=Eq.wt×valency

=3×4=12