Vapour density of N2O4 is 45.86 at a certain
temperature. The degree of dissociation of N204 at
the same temperature would be approximately
(1) 0.003
(2) 0.03
(3) 0.3
(4) 0.0003
Answers
Answered by
1
Answer:
answer is nil 0.0003 bro easy
Answered by
1
Explanation:
Di= initial vapour density
d= vapour density at equilibrium
n= no. of mole of products
molecular weight of N2o4 is = 92
Attachments:
![](https://hi-static.z-dn.net/files/d28/69c2593d192968bbf97ab3a8bd614638.jpg)
princehimu65:
ans is 0.003
Similar questions