Chemistry, asked by hafeezatika45, 6 months ago

Vapour density of N2O4 is 45.86 at a certain
temperature. The degree of dissociation of N204 at
the same temperature would be approximately
(1) 0.003
(2) 0.03
(3) 0.3
(4) 0.0003​

Answers

Answered by jpandidevi13
1

Answer:

answer is nil 0.0003 bro easy

Answered by princehimu65
1

Explanation:

Di= initial vapour density

d= vapour density at equilibrium

n= no. of mole of products

molecular weight of N2o4 is = 92

Attachments:

princehimu65: ans is 0.003
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