Question

vapour density of the equilibrium mixture of no2 and n2o4 is found to be 40 for the equilibrium:n2o4=2no2 calculate percentage of no2 in the mixture​

Answer 1

Answer:

Vapour density of the equilibrium mixture of

and

is found to be

for the equilibrium <br>

<br> Calculate

Answer 2

Explanation:

N

2

O

4

⇌2NO

2

t=0 1

t=t

eq

1−α2α

Initial vapour density of N

2

O

4

=

2

92

=46

Vapour density at equilibrium=40

40

46

=

c

c+cα

40

46

=1+α

1+α

46

=40 46=40+40α

⇒ α−

40

6

=

20

3

∴ % NO

2

=

1+α

2α

×100

=

23

10

×100+

23

6

×100×26.08%

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