Vapour density of the gas is 11.2 volume occupied by 2.4 gram of this is stp will be
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Molecular mass of the gas = 2 x Vapour density of the gas
MM = 2 x 11.2 = 22.4 g/mol
22.4 g of gas = 1 mole of the gas
2.4 g of gas = (1 x 2.4) / 22.4 = 0.107 mole of gas
1 mole of gas = 22.4 L of gas
Therefore, 0.107 mole of gas = (22.4 x 0.107) = 2.39 L of gas
MM = 2 x 11.2 = 22.4 g/mol
22.4 g of gas = 1 mole of the gas
2.4 g of gas = (1 x 2.4) / 22.4 = 0.107 mole of gas
1 mole of gas = 22.4 L of gas
Therefore, 0.107 mole of gas = (22.4 x 0.107) = 2.39 L of gas
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