Question

Vapour density of the gas is 11.2 volume occupied by 2.4 gram of this is stp will be

Answer 1

Molecular mass of the gas = 2 x Vapour density of the gas

MM = 2 x 11.2 = 22.4 g/mol

22.4 g of gas = 1 mole of the gas

2.4 g of gas = (1 x 2.4) / 22.4 = 0.107 mole of gas

1 mole of gas = 22.4 L of gas

Therefore, 0.107 mole of gas = (22.4 x 0.107) = 2.39 L of gas