Question

Vapour Density of the mixture is:-​

Answer 1

$\huge\star {\green\ {\underline{\mathfrak{Answer :-}}}}$

$Vapour\ density\ of\ N_2O_4 = \frac{Molar\ mass\ of\ N_2O_4}{Molar\ mass\ H_2}$

$\\= \frac{92.011}{2.016} = 45.64$

$Vapour\ density\ of\ NO_2 = \frac{ Molar\ mass\ of\ NO_2}{Molar\ mass\ of\ H2 }$

$= \frac{46.0055}{2.016} = 22.82$

$Ratio = 2:1$

$V.D.\ N_2O_4\times 2 = 91.28 + V.D.\  NO_2\times 1 = 22.82$

$= 114.1$

$Average = \frac{114.1}{3}  = 38.033\\\\\\Or\ 38.03$

Answer 2

Answer :-
38.03 (average)