Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 298K are 200 mm of Hg and 415 mm of Hg respectively. Calculate the vapour pressure of solution prepared by mixing 24g of chloroform and 17g of dichloromethane at 298K.
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Explanation:
Vapour pressure of pure chloroform = P
A
o
=200mm
Vapour pressure of pure dichloromethane P
B
o
=415mmHg
Molar mass M
A
=119.5g
Molar mass M
B
=85g
(i) mass of CHCl
3
=25.5g
number of mole =
119.5
25.5
=0.213
Mass of CH
2
Cl
2
=40g
Number of mole =
85
40
=0.47
x
A
=
0.213+0.47
0.213
=0.322
x
B
=1−0.322=0.688
P=P
A
o
X
A
+P
B
o
x
B
=200×0.322+415×0.688
=64.4+285.52=349.92
(ii) Mole fraction of chlotoform = 0.322
Mole fraction of CH
2
Cl
2
=0.688
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