Question

Vapour pressure of pure A (p.) = 100 mm Hg
Vapour pressure of pure B (P.) = 150 mm Hg
2 mol of liquid A and 3 mol of liquid B are mixed to form an ideal solution. The vapour pressure of solution
will be:
(A) 185 mm
(B) 130 mm
(C) 148 mm
(D) 145 mm​

Answer 1

Explanation:

mole fraction a = 2/5

mole fraction b = 3/5

pressure = 100 x 2/5 + 150 x 3/5 = 40+90=130 mm

Answer 2

Answer:

130 mm

Explanation:

first find Xa and Xb

Xa= 2/2+3 Xb= 3/2+3

= 2/5 = 3/5

Ptotal = pA Xa + pB Xb

= 100×2/5 + 150×3/5

= 40+90

Ptotal = 130

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