Question

Vapour pressure of pure liquids a and b are 70mm of hg and 90 mm of hg respectively at 25 degree Celsius the mole fraction of a in the solution of a and b is 0.3 asuming the ideal solution calculte partial pressure of a and b present in equlibrium with the sol

Answer 1

Answer:

hey mate

Explanation:

We kmow that,

According to Dalton's Law of Partial Pressures,

partial Pressure of each component gas is proportional to their mole fractions in the vapour.

Hence,

Partial Pressure of A =Pa=400×0.45=180

Partial Pressure of B= Pb=400×(1−0.45)=220

Also, Partial Pressure of the gas in the vapour

= (Vapour Pressure) × (Mole Fraction of Liquid in solution)

Hence,

Vapour Pressure of A =Va=1800.65≈277

Vb=

(1−0.65)

220

≈629