Question

Vapour pressure of the solution made by dissolving
0.65 g of a non-volatile solute (mol. wt. = 65) in
100 ml CCI, is (density of CCI, = 1.54 g/cmº and
vapour pressure of CCI. = 140mm of Hg)
(1) 199.34 mm (2) 94.39 mm
(3) 145.96 mm (4) 138.6 mm​

Answer 1

Answer:

Vapor pressure of solution = xa(Pa) + xb(Pb)

here na = 0.65 /65 = 0.01 ;

density of CCl = 1.54 g / cm3 , 1 m3 = 1000L so

1000000 cm3 = 1000000 ml === > 1 cm3 = 1 ml

nb = 1.54*100/(12 + 35.5x4) = 154/154 = 1

therefore mole fraction of A =  0.01/1.01 , mole fraction B = 1/1.01

Ptotal = 0.01/1.01 * (0) + 1/1.01 *(140) = 138.6 mm of Hg

Explanation: