Vapour pressure of water at 20°C is 17.5 mm Hg. Calculate the vapour pressure of water at 20°C when 15 g of glucose (Molar mass = 180 g mol-1) is dissolved in 150 g of water.
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17.327 is answer according to me.. see the picture for complete solution
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Answer:
answer is 17.326 mm
Explanation:
According to Raoult's Law
Pa-Ps/Ps=nB/nA
= Wb/Mb x Ma/Wa
17.5mm-Ps/ Ps= 15g / (180 g mol ^-1)
=0.01
17.5mm/Ps-1=0.01
17.5mm/Ps=1.01
Ps=17.5Pm/1.01
Ps=17.326 mm
the vapour pressur of water at 20 degree c when 15 g of glucose is 17.326 mm
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