Chemistry, asked by aleenaD, 11 months ago

vapour pressure of water is 24torr . when urea is added to water having mole fraction 0.25, whats the vapour pressure of solution​

Answers

Answered by priyanshudp2109
1

ANSWER:

We use Raoult's Law........... and calculate a solution vapour pressure of 16⋅mm⋅Hg.

Explanation:

Raoult's Law tells us that in an ideal solution, the vapour pressure of a component is proportional to the mole fraction of that component in solution.

Mole fraction of sucrose: =Moles of sucroseMoles of sucrose + moles of water

χsucrose=200⋅g342.13⋅g⋅mol−1200⋅g342.13⋅g⋅mol−1+112.3⋅g18.01⋅g⋅mol−1=0.0857

Mole fraction of water:

χwater=112.3⋅g18.01⋅g⋅mol−1200⋅g342.13⋅g⋅mol−1+112.3⋅g18.01⋅g⋅mol−1=0.914

Note that by definition, χsucrose+χwater=1

Because sucrose is involatile, the vapour pressure of the solution is proportional to the mole fraction of water:

Psolution=χwater×17.5⋅mm⋅Hg

=0.914×17.5⋅mm⋅Hg=16⋅mm⋅Hg

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