vapour pressure of water is 24torr . when urea is added to water having mole fraction 0.25, whats the vapour pressure of solution
Answers
ANSWER:
We use Raoult's Law........... and calculate a solution vapour pressure of 16⋅mm⋅Hg.
Explanation:
Raoult's Law tells us that in an ideal solution, the vapour pressure of a component is proportional to the mole fraction of that component in solution.
Mole fraction of sucrose: =Moles of sucroseMoles of sucrose + moles of water
χsucrose=200⋅g342.13⋅g⋅mol−1200⋅g342.13⋅g⋅mol−1+112.3⋅g18.01⋅g⋅mol−1=0.0857
Mole fraction of water:
χwater=112.3⋅g18.01⋅g⋅mol−1200⋅g342.13⋅g⋅mol−1+112.3⋅g18.01⋅g⋅mol−1=0.914
Note that by definition, χsucrose+χwater=1
Because sucrose is involatile, the vapour pressure of the solution is proportional to the mole fraction of water:
Psolution=χwater×17.5⋅mm⋅Hg
=0.914×17.5⋅mm⋅Hg=16⋅mm⋅Hg
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