Var (x + 8) is
(a) var (8)
(b) var(x)
(c) 8 var (x)
(d) 0
Answers
Answered by
0
var (X+ any constant ) = var(X)
thus var(X+8) = var (X)
thus option B is correct
general form
var(ax+b) = a²var(X)
thus var(X+8) = var (X)
thus option B is correct
general form
var(ax+b) = a²var(X)
Answered by
3
Hi ,
*********************************************
A discrete random variable X , the
variance of X is written as Var( X ).
Var( aX + b ) = a² Var( X )
Where , a and b are both constants.
********************************************
Now ,
According to the problem given ,
Var ( x + 8 )
= Var ( 1 × x + 8 )
Here , a = 1 , b = 8 ,
= 1² Var( x )
= Var( x )
Therefore ,
Option ( b ) is correct.
I hope this helps you.
: )
*********************************************
A discrete random variable X , the
variance of X is written as Var( X ).
Var( aX + b ) = a² Var( X )
Where , a and b are both constants.
********************************************
Now ,
According to the problem given ,
Var ( x + 8 )
= Var ( 1 × x + 8 )
Here , a = 1 , b = 8 ,
= 1² Var( x )
= Var( x )
Therefore ,
Option ( b ) is correct.
I hope this helps you.
: )
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