Math, asked by kanpariakrishna99, 10 months ago

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Question No. 5
If 3raise to 1215=n raise to n what is the value of n​

Answers

Answered by MasterManasJ
0

Answer:

The idea is simple try all numbers x starting from 2 to square root of n (given number). For every x, try x^y where y starts from 2 and increases one by one until either x^y becomes n or greater than n.

Step-by-step explanation:

Answered by abhijattiwari1215
0

Answer:

The value of n is 243.

Step-by-step explanation:

Given that :

 {3}^{1215}  =  {n}^{n}

To find :

  • Value of n

Solution :

  • Factorising 1215, we get
  • 1215 = 3 x 3 x 3 x 3 x 3 x5
  • Putting this, we get;

 {3}^{3 \times 3 \times 3 \times 3 \times 3 \times 5}  =  {n}^{n}  \\   { {3}^{5 \times (3 \times 3 \times 3 \times 3 \times 3)} } =  {n}^{n} \\  {243}^{243}  =  {n}^{n}

  • Comparing both sides, we get;
  • n = 243
  • Hence, the value of n is 243.
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