Question

Variance of the data 2, 4, 5, 6, 8, 17 is 23.33. Then variance of 4, 8, 10, 12, 16, 34 will be

Answer 1

Here, the variances of data are
2,4,5,6,8,17, is 23.33
Similarly, variencies of
4,8,10,12,16,34, is 46.66

Answer 2

Answer:

93.32

Step-by-step explanation:

If variable of a data set $a_1,a_2,...,a_n$ is $\sigma_1^2$, then the variance of data set $ka_1,ka_2,...,ka_n$ is $k^2\sigma_1^2$.

It is given that variance of the data A= {2, 4, 5, 6, 8, 17} is 23.33.

The new data set is

B = {4, 8, 10, 12, 16, 34}

All terms of this set are twice of set A. Using the above theorem the variance of B is 2² times of variance of set A.

$\sigma_B^2=2^2\times \sigma_A^2$

$\sigma_B^2=4\times \sigma_A^2$

It is given that $\sigma_A^2$ is 23.33.

$\sigma_B^2=4\times 23.33$

$\sigma_B^2=93.32$

Therefore, the variance of 4, 8, 10, 12, 16, 34 will be 93.32.