Physics, asked by aashidewangan, 1 year ago

variation in the value of 'g' with the depth below the surface of the earth

Answers

Answered by iamanupama14
0

Answer:  g' = g (1-x/R)

Explanation:

the answer for the variation in the value of 'g' with the depth below the surface of the earth...

taking g = GM/R² = G/R² 4/3πR²p

where p is density, G is gravitational constant and R is radius...

and further deducing it to get...

g'/g=R-x/R   ....

(i,e)...

              g' = g (1-x/R)

hope it helps

Similar questions