Question

variation of force in certain region is given by 6x^3+4x^2-4x+3.it displaces an object from x =1m to x =b3m in this region find the work done​

Answer 1

$= 6x^3 + 4x ^{2} - 4x + 3 \\ = 6(1)^{3} + 4x ^{2} - 4x + 3 \\ = 6 + 4 - 4 + 3 \\ = 10 - 7 = 3 \\ \\ x = 1 answr \: is \: 3$