Question

variation of g with depth of the earth

Answer 1

Variation of g with depth of the Earth is the addition of acceleration along with the value of g...(g+a)...

Answer 2

$\bold{HEY MATE}$

$HERE IS YOUR ANSWER$

Effect of depth :-
-_--_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-

g = GM/R^2

= G×p/R^2×4/3πR^3

= 4/3GPπR

g' = GM/(R-d)^2

= G×P×4/3×π×(R-d)^3/(R-d)^2

= 4/3GPπ(R-d)

= g'/g = 4/3GPπ(R-d)/4/3GPπR

= (R-d)/R

= R (1-d/R)

g' = g(1-d/r)

=_=_=_=_=_=_=_=_=_=_=_=_=_=_=_=_=_=_=

$I HOPE IT'S HELP YOU$