Question

variation of parameter (D^2+1)y=xsinx​

Answer 1

Answer:

Symbolic form of the given equation, (D2 + 1) y = xsinx Auxiliary equation, D2 + 1 = 0 i.e. D = ±i Thus C.F. = c1y1 + c2y2 = c1cosx + c2sinx … (1) Let P.I. = u1(x)y1 + u2(x)y2; Now by method of variation of parameter Read more on Sarthaks.com - https://www.sarthaks.com/388288/solve-d-2y-dx-2-y-xsinx-using-method-of-variation-of-parameter?show=388294#a388294