varify that 5 and 7 are zero of P (X) = (X+5) (x-7)
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Step-by-step explanation:
P (X) = (X+5) (x-7)
p(5)= (5+5)(5-7)
=10×(-2)= -20
p(5) doesn't equal to zero
so, 5 is not zero of p(x)
p(7)= (7+5)(7-7)=(12)(0)=0
hence, 7 is a zero of p(x)
p(-5)=(-5+5)(-5+7)=0(2)=0
hence, -5 is a zero of polynomial p(x)
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