Question

varun is riding his motorcycle with certain speed. He sees a child in the middle of the
road moving all alone. He suddenly applies brakes of his motorcycle and saves the child.
find his acceleration

Answer 1

Answer:

Given:

Initial speed of the three-wheeler, u=36km/h=10m/s

Final speed of the three-wheeler, v=0 m/s

Time, t=4s

Mass of the three-wheeler, m=400 kg

Mass of the driver, m′=65kg

Total mass of the system, M=400+65=465 kg

Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:

v=u+at

a=t(v−u)=4(0−10)=−2.5m/s2

The negative sign indicates that the velocity of the three-wheeler is decreasing with time.

Using Newton's second law of motion, the net force acting on the three-wheeler can be calculated as:

F=Ma=465×(−2.5)=−1162.5N

The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.