Math, asked by pkmiruthula, 10 months ago

Varun is thrice as old as Banu. four years ago this age was four times Banu's age. the present age of Varun is ​

Answers

Answered by Ishrat9C
0

Answer:

48 years old

Step-by-step explanation:

Let varun's present age be= 3x

so banu's age is =  x

4 years ago,

so varun= 3x-4

and banu=x-4

ATQ,

3x=4(x-4)

3x=4x-16

4x-3x=16

x=16

so varun's age is  3x

3(16)

48 years old

Hope you find this helpful

Answered by Anonymous
0

Let's assume Varun as V and Banu as B.

• The age is varun is three times the age of Banu.

So,

v = 3b __(1

• Four year ago Varun was four times the age of her.

Their ages before 4 years were : v-4 and b-4

So,

(v-4) = 4(b-4) __(2

Now,

by substituting the value of first eq.1 in eq.2 :

(3b - 4) = 4(b - 4)

= 3b - 4 = 4b - 16

= 12 = b

Therefore, bhanuz age is 12.

Than Varunz age is 12 * 3 = 36

Verification :

v-4 = 4(b-4)

36 - 4 = 4(12 - 4)

32 = 32

LHS = RHS

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