Question

Varun throws a die at random find the probability of getting (i) a number > 4
(ii) a number <3
(iii) number 5 ​

Answer 1

Step-by-step explanation:

s={ 1,2,3,4,5,6}

n(s) = 6

1]. A= { 5,6}

n(A)= 2

2] B={ 2,1}

n(B)= 2

3]C={5}

n(C)=1

P(A)=n(A)/n(S)= 2/6=1/3

P(B)= n(B)/n(S)=2/6=1/3

P(C)= n(C)/n(S)=1/6

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Answer 2

Answer:

Step-by-step explanation:

s={ 1,2,3,4,5,6}

n(s) = 6

1]. A= { 5,6}

n(A)= 2

2] B={ 2,1}

n(B)= 2

3]C={5}

n(C)=1

P(A)=n(A)/n(S)= 2/6=1/3

P(B)= n(B)/n(S)=2/6=1/3

P(C)= n(C)/n(S)=1/6