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Answer:
Explanation:
We know that, R = V^2 /P
Hence resistance of 1st bulb = (250)^2 / 200 = 625/2
resistance of 2nd bulb = (250)^2 / 100 = 625
Total resistance of the circuit when the bulbs are connceted in series = 625/2 + 625 = 1875/2 ohm
Therefore, total power consumed in the circuit , P = (250)^2 / (1875/2) = 67 watt
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Answer:
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