Question

vasu is 3 year younger than a sibling 5 year ago he was 6 less than twice Arun age find their present ages​

Answer 1

Answer:

${\huge{\pink{\underline{\underline{QuEsTiOn}}}}}$

• vasu is 3 year younger than a sibling 5 year ago he was 6 less than twice Arun age find their present ages

${\huge{\pink{\underline{\underline{AnSwEr}}}}}$

Let the age of Vasu be x

age of Arun be y

x=y-3

=>x=-3+y

=>x-y=-3 -------eq. 1

5 years ago,age of vasu be (x-5)

age of varun be(y-5)

According to question...

x-5=2(y-5)-6

=>x-5=2y-10-12

=>x-2y=-22+5

=>x-2y=-17 --------eq. 2

Now,subtracting eq.1 from eq.2

x-y-(x-2y)=-3-(-17)

=>x-x-y+2y=-3+17

=>y=14...

So,the age of arun is y=14yrs.

age of vasu =by solving eq. 1 with putting the value of y..

A/Q

x-14=-3

=>x=-3+14

=>x=11yrs.

Age of vasu=11 yrs.

Answer 2

Answer:

ꦿ᭄★ ANSWER ★᭄ꦿ᭄

Let the age of Vasu be x

age of Arun be y

x=y-3

=>x=-3+y

=>x-y=-3 -------eq. 1

5 years ago,age of vasu be (x-5)

age of varun be(y-5)

According to question...

x-5=2(y-5)-6

=>x-5=2y-10-12

=>x-2y=-22+5

=>x-2y=-17 --------eq. 2

Now,subtracting eq.1 from eq.2

x-y-(x-2y)=-3-(-17)

=>x-x-y+2y=-3+17

=>y=14...

So,the age of arun is y=14yrs.

age of vasu =by solving eq. 1 with putting the value of y..

A/Q

x-14=-3

=>x=-3+14

=>x=11yrs.

Age of vasu=11 yrs.