Question

Vasudevan invested 60.000 at an interest rate of 12% per annum compounded
half yearly. What amount would he get
(1) after 6 months?
(ii) after 1 years ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\huge \bold \color{green} ✯ \mathfrak \red {required \: answer}✔︎$

$\bold { \underline{ \underline \orange{given}}} \orange→$

p = 60,000

r = 12%

we know that,

$\huge\bold \color{pink}a = p(1 + \frac{r}{200} )^{2n}$

i).amount after 6 month?

n = 6 months = 1/2 year

$\bold{a1 = 60000(1 + \frac{12}{200}) ^{2 + \frac{1}{2} } } \\ \\ \bold{\implies \: 60000(1.06) \: \: \: \: \: \: \: } \\ \\ \bold{ \implies \: 63600 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

so amount would he get after 6 months is Rs. 63,600

ii). amount after 1 year?

n = 1 year

$\bold{a2 = 60000(1 + \frac{12}{200} )} ^{2 \times 1} \\ \\ \bold{ \implies60000(1.1236)} \\ \\ \bold{ \implies \: 67416 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

so amount would he get after 1 year is Rs. 67416

$\bold { \underline{ \underline \orange{for \: more \: information}}} \orange→$

• A = final amount
• P = initial principal balance
• n = no. of times interest applied per time
• t = time period elapsed

• SI = P×R×T/100
• A = p(1+rt)