Question

vé. A rubber ball of mass 0.05 kg is thrown against a wall. It strikes the wall normally with
a velocity of 25 m/s and rebounds with the same speed in the opposite direction. Calculate the
impulse of the force exerted by the wall on the ball.
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Answer 1

0

Given,

mass of a ball=0.05 kg

velocity of the ball=25 m/s

returning velocity= intial velocity= 25 m/s

so,

impulse= mv-mu

= m(v-u)

=0.05(25-25)

=0.05×0

=0

hope it helps you.....