Question

ve and
Find the area of the region in the first quadrant that is bounded above by y =
$\sqrt[]{x}$

below by the x-axis and the line y = x - 2
(4,2)
2
x=y²
y= X-2
(x = y+2)
A
X
4
- 1
(1,-1)​

Answer 1

Answer:

y=x-2 wher x=y²

y=y²-2

y²=y+2

y=root y+2