Question

Vector A is 2cm long and 60degree Above the x axis in first quadrant . Vector B is 2cm long and 60degree below the x axis in the fourth quadrant .the sum of vector A and B is a vector of magnitude

Answer 1

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Answer 2

Answer:

The magnitude of the resultant is 2.4

Explanation:

Given that,

$\vec{A}= 2 cm$

Angle $\theta = 60^{\circ}$

$\vec{B}= 2 cm$

Angle $\theta = 60^{\circ}$

We know that whenever two equal vectors are added and angle between them 120° then the resultant of the vector will be

The magnitude of the sum of vector A and B is

$|R|=\sqrt{A^2+B^2+2ABcos\ \theta}$

$|R|=\sqrt{2^2+2^2+2\times2\times\ cos\ 120^{\circ}}$

$|R|=\sqrt{2^2+2^2+2\times2\times\dfrac{-1}{2}}$

$|R|=2.4$

Hence, The magnitude of the resultant is 2.4