Vector A is 8m along the horizontal & vector B is 10m at 90 digre to horizontal calculate A B
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As A=8m and B =10m and angle between them is 90° . As we know A.B=AB cos thita
Therefore A.B =80 cos 90 =0
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Dear Student,
● Answer -
AB = 12.8 m
◆ Explaination -
# Given -
A = 8 m
B = 10 m
θ = 90°
# Solution -
Resultant vector AB is given by formula -
R = √(x^2 + y^2 + 2xycosθ)
Here,
AB = √(A^2 + B^2 + 2×A×B×cosθ)
AB = √(8^2 + 10^2 + 2×8×10×cos90°)
AB = √(64 + 100 + 160×0)
AB = √(164)
AB = 12.8 m
Hence, resultant vector AB is 12.8 m.
Thanks dear. Hope this is helpful to you...
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