Question

Vector A . Vector B = (A CosØ)B

Answer 1

Explanation:

Correct option is C)

A

=

i

^

Acosθ+

j

^

Asinθ and consider

A

=

i

^

x+

j

^

y. Now, B is normal to A then:

A

.

B

=0

A

.

B

=(

i

^

Acosθ+

j

^

Asinθ).(

i

^

x+

j

^

y)

=Axcosθ+Aysinθ

Therefore, for

A

.

B

=0 x should be of form Bsinθ and y of form −Bcosθ