Vector A -(x i cap+6j cap) m/s and vector B - (3 i cap +2 j cap) m/s, find x such that the relative speed of A with
respect to B becomes 5 m/s..
A. 3
B. 4
C. 5
D. 6
Answers
Answered by
0
Answer:
3 are correct
Explanation:
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Answered by
10
Answer:
option (d) : 6
Explanation:
The velocity of a body A is xi^+6j^ m/s and the velocity of a body B is 3i^+2j^ m/s. Find the value of x such that the relative speed of A with respect to B becomes 5 m/s.
Relative velocity of A w.r.t B =║A- B ║ = 5
∴ A - B
=(xi+6j)-(3i+2j)=(x-3)i+(6-2)j
(x-3)i+4j=5
║A - B║ = 5
√[ (x-3) ² + (4)²] = 5
x² + 9 - 6x + 16 = 25
x² - 6x = 0
x(x - 6) = 0
x = 0 or x = 6
2
- 6x+9+16=25
X
2
=6x
Or the value of x is given by
X=6
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