Question

Vector c and d have magnitude of3 units and 4 units , respectively . What is the angle between the of vector c and d if vector c.d equals ( a) zero ( b)12 ( c) -12 units

Answer 1

Answer:

(a) 90°

(b) 0°

(c) 180°

Explanation:

|c| = 3

|d|= 4

dot product of two vectors if they make

¢ angle with each other

c.d= |c| |d| cos¢

(a) 0 = 3*4*cos¢

cos¢= 0

¢= 90°

(b) 12= 3*4*cos¢

cos¢= 1

¢= 0°

(c) -12= 3*4*cos¢

cos¢= -1

¢= 180