Question

vector f = 2i^+3j^+k acts on body of mass 0.2kg find 1) acceleration of the body 2) change in the velocity of the body in 3 seconds 3) change in momentum of the body on 3 second if F is expressed in the newton
It's really very very urgent ​

Answer 1

magnitude of force =√2^2+3^2+1^2

=√4+9+1

=√14=3.74

1)F=ma

a=F/m

a=3.74/.2

a=18.7m/s²

2)a=v/t

v=a*t

v=18.7*3=56.1m/s

3)f=p/t

p=f*t

p=3.74*3=11.22