Vector ⃗ has a magnitude of 6.00 units, vector ⃗⃗ has a magnitude of 7.00 units and ⃗. ⃗⃗
has a value of 14.0. What is the angle between the directions of ⃗ and ⃗⃗?.
Answers
Answered by
0
Explanation:
Apply the dot product definition
→
A
.
→
B
=
∣
∣
∣
→
A
∣
∣
∣
⋅
∣
∣
∣
→
B
∣
∣
∣
⋅
cos
θ
Where
The angle between the
2
vectors is
=
θ
Plugging in the values in the equation
14
=
17
×
9.2
⋅
cos
θ
cos
θ
=
14
17
×
9.2
=
0.09
Therefore,
θ
=
arccos
(
0.09
)
=
84.9
∘
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